### Estimating Irrigation Demand of Residential Subdivisions
A common problem in the design of a public water supply and distribution systems is how to estimate the effect on peak hour demand in a predominantly residential system when a large number of the connections begin simultaneous irrigation. Irrigation demand for single residential connections often far exceed normal household use. It is impractical to design a public water supply system to simultaneously serve 100% of such connections, yet to not to design a system for a reasonable expected number of connections simuitaneously irrigating may result in low pressure problems. This technical topic provides one theoretical approach to the problem
The following example calculation indicates one method irrigation demand for residential subdivisions with in ground lawn sprinkler systems could be estimated. There are many assumptions that have to be made after the size of the lot and dwelling are established. In this example, it is assumed that the grassed area of the lot is irrigated at 1 inch per week. This results in average day demand of 669 gallons per day* per lot. *While high, this is not altogether unusual.
Site of lot |
0.25 |
ac |
Size of Dwelling and Driveway |
3375 |
sf |
Average Irrigation Rate |
1 |
in/wk |
average gallons per day |
669 |
gpd |
Average Sprinkler Head |
2 |
gpm/each |
Coverage' |
680 |
sf/each |
Number of Heads |
11 |
Zones |
2 |
Domestic Demand |
1 |
Demand Per Home |
13 |
gpm |
Irrigation Time Per day |
51 |
minutes |
Probability One On, any time |
0.053 |
The instantaneous demand per connection has to be estimated. There are several ways to do this, but considering a reasonable number of zones and gallons per minute per emitter or sprinkler head, it is likely that 13 gpm or more will be the instantaneous irrigation demand from one lot. Thus, the typical home would satisfy their irrigation requirement of 1 inch per week with just over 50 minutes of operation per day.
If we then assume then that for all intents and purposes that people will only irrigate their lawns between 6 in the morning and 10 at night, then the probability that one home would be irrigating at any one time is about 5%.
With a hundred homes, the question then becomes how likely is it that 5, 10, 15 etc, homes could be *simultaneously* irrigating.
Use of the so-called binomial formula suggests the following :
From this chart, we can see that of 100 homes, it is most likely that 5 would be irrigating at any one time. However, we are not concerned with what is most likely to occur on a typical day, but what could occur given enough time that would cause us supply and pressure problems. With this view, we see that it is not until we anticipate more than 14 or 15 homes out of 100 simultaneously irrigating that the probability of such occurring drops to less than 1 percent.
Thus, in this case, our suggested instantaneous irrigation demand for the 100 homes would be :
100 x 15% x 13 gpm per home = 195 gpm. To that we need to add the ordinary peak demand for the rest of the homes which are not irrigating, which is probably 100 gpm. Total demand is therefore practically 300 gpm.
If the distribution system piping is designed to transmit fireflows of at least 500 gpm, then it is likely that it will handle irrigation demand as well. However, there may be cases where this is not so.
A final note: no mathematical exercise can entirely substitute for real data. If possible, surveys of neighborhoods where high irrigation demands are thought to occur should be checked. |